一、Oracle根据身份证判断性别:

女生身份证:

431382198103246985

男生身份证:

150921197208173492

SQL语句如下:

select decode(mod (to_number(substr(‘110228197802199547’ ,17, 1)),2 ),0, ‘女’,’男’ ) as sex from dual ;

select decode(mod (to_number(substr(‘530323197503252610’ ,17, 1)),2 ),0, ‘女’,’男’ ) as sex from dual ;

select decode(mod (to_number(substr(‘110228197802199547’ ,17, 1)),2 ),0, ‘2’,’1′ ) as sex from dual ;

select decode(mod (to_number(substr(‘530323197503252610’ ,17, 1)),2 ),0, ‘2’,’1′ ) as sex from dual ;

二、Oracle根据身份证判断年龄:

select (to_char(sysdate, 'yyyy') - substr('430426199303014475', 7, 4)) age from dual;

方法二

select trunc(to_number(to_char(sysdate,'yyyymmdd'))/10000 - to_number(to_char(to_date('1982-8-28','yyyy-mm-dd'),'yyyymmdd'))/10000) from dual

方法三

select trunc((to_char(sysdate,'yyyyMMdd')-to_char(to_date(substr('430426199303014475',7,8),'yyyy-MM-dd'),'yyyyMMdd'))/10000)  from dual;